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Phrases Trigonometry PYQ



The expression  tanA1cotA+cotA1tanA can be written as 





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Angle of elevation of the top of the tower from 3 points (collinear) A, B and C on a road leading to the foot of the tower are 30°, 45° and 60°, respectively. The ratio of AB and BC is





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Solution

According to the given information, the figure should be as follows.  
Let the height of tower = h




If 3sinx+4cosx=5, then 6tanx29tan2x2 





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Largest value of cos2θ6sinθcosθ+3sin2θ+2 is





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Number of point of which f(x) is not differentiable f(x)=|cosx|+3 in [π,π]





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Solution

Points of Non-Differentiability of f(x)=|cosx|+3

Step 1: cosx is differentiable everywhere, but |cosx| is not differentiable where cosx=0.

Step 2: In the interval [π,π], we have:

cosx=0x=π2, π2

So f(x)=|cosx|+3 is not differentiable at these two points due to sharp turns.

✅ Final Answer:   2 points



If A > 0, B > 0 and A + B = π6 , then the minimum value of tanA+tanB





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Solution

On differentiating 
x= tanA + tan(π/6-A) 
we get : 
dx/dA = sec²A-sec²(π/6-A) 
now putting 
dx/dA=0 
we get 
cos²(A) = cos²(π/6-A) so 0≤A≤π/6 
therefore 
A=π/6-A from here we get A = π/12 = B 
so minimum value of that function is 
2tanπ/12 which is equal to 2(2-√3)


The sin2xtanx+cos2xcotxsin2x=1+tanx+cotx, x(0,π), then x





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If cosecθcotθ=2, then the value of cosecθ is





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The solution of the equation 4cos2x+6sin2x=5 are





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The value of tan(π4+θ)tan(3π4+θ) is





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Solution

We are given:

Evaluate tan(π4+θ)tan(3π4+θ)

✳ Step 1: Use identity

tan(A+B)=tanA+tanB1tanAtanB

But we don’t need expansion — use known angle values:

tan(π4+θ)=1+tanθ1tanθ

tan(3π4+θ)=1+tanθ1+tanθ

✳ Step 2: Multiply

(1+tanθ1tanθ)(1+tanθ1+tanθ)

Simplify:

=(1+tanθ)(1+tanθ)(1tanθ)(1+tanθ)=(tan2θ1)1tan2θ=1

✅ Final Answer:

1



If sinx=siny and cosx=cosy, then the value of x-y is





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Solution

Given:

sinx=sinyandcosx=cosy

✳ Step 1: Use the identity for sine

sinx=sinyx=y+2nπorx=πy+2nπ

✳ Step 2: Use the identity for cosine

cosx=cosyx=y+2mπorx=y+2mπ

? Combine both conditions

For both sinx=siny and cosx=cosy to be true, the only consistent solution is:

x=y+2nπxy=2nπ

✅ Final Answer:

xy=2nπfor nZ



If a1,a2,a3,...an, are in Arithmetic Progression with common difference d, then the sum (sind)(coseca1.coseca2+coseca2.coseca2+...+cosecan1.cosecan) is equal to





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In a ΔABC, if tan2A2+tan2B2+tan2C2=k , then k is always





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The general value of θ, satisfying the equation sinθ=12,tanθ=13





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If  then the value of  is





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If tan x = - 3/4 and 3π/2 < x < 2π, then the value of sin2x is





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The value of tan9tan27tan63+tan81 is equal to





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If cosθ = 4/5 and cosϕ = 12/13, θ and ϕ both in the fourth quadrant, the value of cos( θ + ϕ )is





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The value of sin36o is





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Express (cos 5x – cos7x) as a product of sines or cosines or sines and cosines,





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If 32tan8θ=2cos2α3cosα and 3cos2θ=1, then the general value of α =





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If |k|=5 and 0° ≤ θ ≤ 360°, then the number of distinct solutions of 3cos⁡θ + 4sin⁡θ = k is
NIMCET 2021





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If , then value of 





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If acosθ+bsinθ=2 and asinθbcosθ=3 , then a2+b2=





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The value of tan 1° tan 2° tan 3° ... tan 89° is:





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If P=sin20θ+cos48θ then the inequality that holds for all values of is





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Solution



If sinx+acosx=b, then |asinxcosx| is:





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If 0<x<π and cosx+sinx=12 , then the value of tan x is





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If tan A - tan B = x and cot B - cot A = y, then cot (A - B) is equal to





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The value of sin 20° sin 40° sin 80° is





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In a right angled triangle, the hypotenuse is four times the perpendicular drawn to it from the opposite vertex. The value of one of the acute angles is





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If ni=1tan(αi)=1αi[0,π2] where i=1,2,3,...,n. Then maximum value of ni=1sin(αi).





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Solve the equation sin2 x - sinx - 2 = 0 for for x on the interval 0 ≤ x < 2π





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If tanx2=tanx3=tanx5 and x + y + z = π, then the value of tan2x + tan2y + tan2z is





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Find the value of sin 12°sin 48°sin 54°





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If cos x = tan y , cot y = tan z and cot z = tan x, then sinx =





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The value of tan(7π8) is





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The value of  is





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The value of sin 10°sin 50°sin 70° is





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Solution

sin10° sin50° sin70°
= sin10° sin(60°−10°) sin(60°+10°)
= 1/4 sin3x10°
=1/4x1/2=1/8


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